What is the derivative of (x^2-2/(2x+1)) ?

The derivative of (x^2-2/(2x+1)) is (2x^2+2x+4)/((2x+1)^2)

What is the first derivative of (x^2-2/(2x+1)) ?

The first derivative of (x^2-2/(2x+1)) is (2x^2+2x+4)/((2x+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{2} - 2}{2 x + 1})

\frac{2 x ^{2} + 2 x + 4}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 2}{2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 2 ) ( 2 x + 1 ) - \frac{d}{d x} ( 2 x + 1 ) ( x ^{2} - 2 )}{( 2 x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 2) = 2 x

\frac{d}{d x} (2 x + 1) = 2

= \frac{2 x ( 2 x + 1 ) - 2 ( x ^{2} - 2 )}{( 2 x + 1 ) ^{2}}

Expand

2 x (2 x + 1) - 2 (x^{2} - 2) : 2 x^{2} + 2 x + 4

= \frac{2 x ^{2} + 2 x + 4}{( 2 x + 1 ) ^{2}}

\int ln (x^{2}) d x

\frac{x d y}{d x} + y = e^{- x}

9 y^{^{''}} + 6 y^{^{'}} + 6 y = 0

\int_{3}^{4} 15 x (x - 2)^{4} d x

\int 2 x^{2} e^{- x} d x

What is the derivative of (x^2-2/(2x+1)) ?
The derivative of (x^2-2/(2x+1)) is (2x^2+2x+4)/((2x+1)^2)
What is the first derivative of (x^2-2/(2x+1)) ?
The first derivative of (x^2-2/(2x+1)) is (2x^2+2x+4)/((2x+1)^2)