What is the solution for (xdy)/(dx)+y=e^{-x} ?

The solution for (xdy)/(dx)+y=e^{-x} is y=-(e^{-x})/x+(c_{1})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(xdy)/(dx)+y=e^{-x}

\frac{x d y}{d x} + y = e^{- x}

y = - \frac{e ^{- x}}{x} + \frac{c _{1}}{x}

Solution steps

\frac{x d y}{d x} + y = e^{- x}

Solve linear ODE:

y = - \frac{e ^{- x}}{x} + \frac{c _{1}}{x}

y = - \frac{e ^{- x}}{x} + \frac{c _{1}}{x}

9 y^{^{''}} + 6 y^{^{'}} + 6 y = 0

\int_{3}^{4} 15 x (x - 2)^{4} d x

\int 2 x^{2} e^{- x} d x

x^{2} e^{2 x}

\int tan^{4} (x) d x

What is the solution for (xdy)/(dx)+y=e^{-x} ?
The solution for (xdy)/(dx)+y=e^{-x} is y=-(e^{-x})/x+(c_{1})/x