What is the solution for 7x(x+3y)y^'=7y(x-3y) ?

The solution for 7x(x+3y)y^'=7y(x-3y) is y= x/(3\W(\frac{x^2){c_{1}})}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7x(x+3y)y^'=7y(x-3y)

7 x (x + 3 y) y^{^{'}} = 7 y (x - 3 y)

y = \frac{x}{3 W ( \frac{x ^{2}}{c _{1}} )}

Solution steps

7 x (x + 3 y) y^{'} (x) = 7 y (x - 3 y)

Solve using substitution:

y = \frac{x}{3 W ( \frac{x ^{2}}{c _{1}} )}

y = \frac{x}{3 W ( \frac{x ^{2}}{c _{1}} )}

5 \frac{d r}{d s} = e^{r - 8 s}

\frac{\partial}{\partial x} (4 y^{2} - x^{2})

\int_{- 1}^{5} x^{2} - 4 x - 5 d x

y^{^{'}} + 4 x y^{4} = 0

\frac{d}{d x} (\frac{x + 1 - 1}{x})

What is the solution for 7x(x+3y)y^'=7y(x-3y) ?
The solution for 7x(x+3y)y^'=7y(x-3y) is y= x/(3\W(\frac{x^2){c_{1}})}