What is the integral of (10)/(x-5) ?

The integral of (10)/(x-5) is 10ln|x-5|+C

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integral of (10)/(x-5)

\int \frac{10}{x - 5} d x

10 ln ∣ x - 5 ∣ + C

Solution steps

\int \frac{10}{x - 5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x - 5} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 10 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 10 ln ∣ u ∣

Substitute back

u = x - 5

= 10 ln ∣ x - 5 ∣

Add a constant to the solution

= 10 ln ∣ x - 5 ∣ + C

f (x) = 2 x^{2} - 7 x + 5, at x = 3

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