What is the tangent of f(x)=-2-cos(x),\at x=-pi/4 ?

The tangent of f(x)=-2-cos(x),\at x=-pi/4 is y=-(sqrt(2))/2 x-2-1/(sqrt(2))-pi/(4sqrt(2))

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tangent of f(x)=-2-cos(x),\at x=-pi/4

tangent of

f (x) = - 2 - cos (x), at x = - \frac{π}{4}

y = - \frac{2}{2} x - 2 - \frac{1}{2} - \frac{π}{4 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, - 2 - \frac{1}{2})

Find the slope of

f (x) = - 2 - cos (x) : \frac{df ( x )}{d x} = sin (x)

Compute the slope of

f (x) = - 2 - cos (x)

x = - \frac{π}{4} : m = - \frac{2}{2}

Find the line with slope m=

- \frac{2}{2}

and passing through

(- \frac{π}{4}, - 2 - \frac{1}{2}) : y = - \frac{2}{2} x - 2 - \frac{1}{2} - \frac{π}{4 2}

y = - \frac{2}{2} x - 2 - \frac{1}{2} - \frac{π}{4 2}

\frac{1}{( s - 1 )}

f (x) = x^{2} - 7, (2, - 3)

\frac{d}{d x} ((ln (x + 1))^{2})

y = 9 x, y = x^{2} - 10, y = 0

What is the tangent of f(x)=-2-cos(x),\at x=-pi/4 ?
The tangent of f(x)=-2-cos(x),\at x=-pi/4 is y=-(sqrt(2))/2 x-2-1/(sqrt(2))-pi/(4sqrt(2))