What is the derivative of (2x-2)^4(x^2+x+1)^4 ?

The derivative of (2x-2)^4(x^2+x+1)^4 is 8(2x-2)^3(x^2+x+1)^4+4(x^2+x+1)^3(2x+1)(2x-2)^4

What is the first derivative of (2x-2)^4(x^2+x+1)^4 ?

The first derivative of (2x-2)^4(x^2+x+1)^4 is 8(2x-2)^3(x^2+x+1)^4+4(x^2+x+1)^3(2x+1)(2x-2)^4

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derivative of

(2 x - 2)^{4} (x^{2} + x + 1)^{4}

8 (2 x - 2)^{3} (x^{2} + x + 1)^{4} + 4 (x^{2} + x + 1)^{3} (2 x + 1) (2 x - 2)^{4}

Solution steps

\frac{d}{d x} ((2 x - 2)^{4} (x^{2} + x + 1)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (2 x - 2)^{4}, g = (x^{2} + x + 1)^{4}

= \frac{d}{d x} ((2 x - 2)^{4}) (x^{2} + x + 1)^{4} + \frac{d}{d x} ((x^{2} + x + 1)^{4}) (2 x - 2)^{4}

\frac{d}{d x} ((2 x - 2)^{4}) = 8 (2 x - 2)^{3}

\frac{d}{d x} ((x^{2} + x + 1)^{4}) = 4 (x^{2} + x + 1)^{3} (2 x + 1)

= 8 (2 x - 2)^{3} (x^{2} + x + 1)^{4} + 4 (x^{2} + x + 1)^{3} (2 x + 1) (2 x - 2)^{4}

7 sec^{5} (π t - 8)

\int \frac{1}{( 225 - x ^{2} ) ^{\frac{3}{2}}} d x

(y^{2} sin (x)) d x + (\frac{1}{x} - \frac{y}{x}) d y = 0

x \to 4 lim (\frac{8 - 2 x}{x - 4})

\frac{d}{d x} (\frac{1}{( x - 4 ) ^{2}})

What is the derivative of (2x-2)^4(x^2+x+1)^4 ?
The derivative of (2x-2)^4(x^2+x+1)^4 is 8(2x-2)^3(x^2+x+1)^4+4(x^2+x+1)^3(2x+1)(2x-2)^4
What is the first derivative of (2x-2)^4(x^2+x+1)^4 ?
The first derivative of (2x-2)^4(x^2+x+1)^4 is 8(2x-2)^3(x^2+x+1)^4+4(x^2+x+1)^3(2x+1)(2x-2)^4