What is the derivative of y=3e^x+4/(\sqrt[3]{x)} ?

The derivative of y=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}

What is the first derivative of y=3e^x+4/(\sqrt[3]{x)} ?

The first derivative of y=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}

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derivative of

3 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= 3 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{3 x ^{3} + 7}{x}

\frac{d}{d x} ((3 x - 1)^{4})

\frac{d}{d x} (- cos (2 x) - sin (2 x) - \frac{1}{5} e^{x})

2 \frac{d y}{d x} + 6 y = 3

\frac{d}{d x} ((2 x^{3} - 3 x + 2)^{4})

What is the derivative of y=3e^x+4/(\sqrt[3]{x)} ?
The derivative of y=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}
What is the first derivative of y=3e^x+4/(\sqrt[3]{x)} ?
The first derivative of y=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}