What is the derivative of-sin(2x2) ?

The derivative of-sin(2x2) is -4cos(2x)

What is the first derivative of-sin(2x2) ?

The first derivative of-sin(2x2) is -4cos(2x)

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\frac{d}{d x} (- sin (2 x) 2)

- 4 cos (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 2 cos (2 x) \cdot 2

Simplify

= - 4 cos (2 x)

(x - 1) y^{^{'}} + (x - 2) y = 0

\frac{d}{d x} (- 2 cos (x))

y ln (x) ln (y) d x + d y = 0

\int \frac{2 ^{x}}{3 ^{x}} d x

\frac{d}{d x} (6 x cos (x^{2}))

What is the derivative of-sin(2x2) ?
The derivative of-sin(2x2) is -4cos(2x)
What is the first derivative of-sin(2x2) ?
The first derivative of-sin(2x2) is -4cos(2x)