What is the slope ofintercept (-1,1),(1,-2) ?

The slope ofintercept (-1,1),(1,-2) is y=-3/2 x-1/2

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slope ofintercept (-1,1),(1,-2)

slope intercept

(- 1, 1), (1, - 2)

y = - \frac{3}{2} x - \frac{1}{2}

Solution steps

Compute the slope

(- 1, 1), (1, - 2) : m = - \frac{3}{2}

Compute the

y

intercept:

b = - \frac{1}{2}

Construct the line equation

y = mx + b

where

m = - \frac{3}{2}

and

b = - \frac{1}{2}

y = - \frac{3}{2} x - \frac{1}{2}

x \to 0 lim (\frac{tan ( 2 ) ( x )}{x})

2 x^{8} e^{x}

\int \frac{1}{4 x} d x

\frac{d}{d x} (4 x^{3} + 5 x)

\frac{d}{d x} (arctan (\frac{5}{x}))

What is the slope ofintercept (-1,1),(1,-2) ?
The slope ofintercept (-1,1),(1,-2) is y=-3/2 x-1/2