What is inverse oflaplace (e^{-3s})/s ?

The answer to inverse oflaplace (e^{-3s})/s is \H(t-3)

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inverse oflaplace (e^{-3s})/s

inverse laplace

\frac{e ^{- 3 s}}{s}

H (t - 3)

Solution steps

L^{- 1} {\frac{e ^{- 3 s}}{s}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Where

H (t)

is Heaviside step function

= H (t - 3) L^{- 1} {\frac{1}{s}} (t - 3)

L^{- 1} {\frac{1}{s}} : H (t)

= H (t - 3) H (t - 3)

= H (t - 3)

\frac{d}{d x} (- arcsin (\frac{1}{x}) + e^{2})

f (x) = [ln (x)]^{x}

y^{'} = 0.0015 y (2100 - y)

\frac{d y}{d x} = x^{\frac{3}{2}}

\int - \frac{1}{n ^{2}} cos (n t) d t

What is inverse oflaplace (e^{-3s})/s ?
The answer to inverse oflaplace (e^{-3s})/s is \H(t-3)