What is the tangent of f(x)=(2x-5)^3,\at x=1 ?

The tangent of f(x)=(2x-5)^3,\at x=1 is y=54x-81

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tangent of f(x)=(2x-5)^3,\at x=1

tangent of

f (x) = (2 x - 5)^{3}, at x = 1

y = 54 x - 81

Solution steps

Find the tangent point:

(1, - 27)

Find the slope of

f (x) = (2 x - 5)^{3} : \frac{df ( x )}{d x} = 6 (2 x - 5)^{2}

Compute the slope of

f (x) = (2 x - 5)^{3}

x = 1 : m = 54

Find the line with slope m=

54

and passing through

(1, - 27) : y = 54 x - 81

y = 54 x - 81

\int e^{8 x} cos (3 x) d x

f (x) = 6 tan (x), at x = \frac{π}{3}

\frac{\partial}{\partial x} (2 x - 1)

\int x y + 1 d y

\frac{1}{( t + 1 ) ^{2}}

What is the tangent of f(x)=(2x-5)^3,\at x=1 ?
The tangent of f(x)=(2x-5)^3,\at x=1 is y=54x-81