Solution
Solution
+1
Solution steps
Apply u-substitution
Complete the square
Apply u-substitution
Take the constant out:
Expand
Apply the Sum Rule:
Simplify
Popular Examples
area y=sqrt(5x),y=2x-5,y=0limit as x approaches 4 of 6x^2-10y^'=xy+x-2y-2sum from n=2 to infinity of ln(1-1/(n^2))tangent of y=(x^2)/(x-8),(2, 2/5)
Frequently Asked Questions (FAQ)
What is the integral from 0 to 1 of (x-9)/(x^2-5x+6) ?
The integral from 0 to 1 of (x-9)/(x^2-5x+6) is (-ln(3)+13ln(3/4))/2