What is the tangent of x^2+3x,\at x=0 ?

The tangent of x^2+3x,\at x=0 is y=3x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^2+3x,\at x=0

tangent of

x^{2} + 3 x, at x = 0

y = 3 x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

y = x^{2} + 3 x : \frac{d y}{d x} = 2 x + 3

Compute the slope of

y = x^{2} + 3 x

x = 0 : m = 3

Find the line with slope m=

3

and passing through

(0, 0) : y = 3 x

y = 3 x

\int - 5 ln (x^{2} - 1) d x

f (x) = (2 x^{2} + 3)^{3} (x^{2} - 4)^{2}

\int (5 cos (x) - 2 sec^{2} (x)) d x

\frac{d}{d v} (ln (u cos (v)))

\int 9 t^{2} d t