What is the solution for y^'+y/t =6cos(5t) ?

The solution for y^'+y/t =6cos(5t) is y=(6(5tsin(5t)+cos(5t))}{25t}+\frac{c_{1})/t

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y^'+y/t =6cos(5t)

y^{^{'}} + \frac{y}{t} = 6 cos (5 t)

y = \frac{6 ( 5 t sin ( 5 t ) + cos ( 5 t ) )}{25 t} + \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{y}{t} = 6 cos (5 t)

Solve linear ODE:

y = \frac{6 ( 5 t sin ( 5 t ) + cos ( 5 t ) )}{25 t} + \frac{c _{1}}{t}

y = \frac{6 ( 5 t sin ( 5 t ) + cos ( 5 t ) )}{25 t} + \frac{c _{1}}{t}

\int x^{2} (x^{3} + 8)^{11} d x

x \to 0 lim (2 x^{2} - 3)

\int_{6}^{12} 6 e^{x} d x

y^{^{'}} = \frac{e ^{t - y}}{1 + e ^{t}}

x \to \infty lim (e^{- π})

What is the solution for y^'+y/t =6cos(5t) ?
The solution for y^'+y/t =6cos(5t) is y=(6(5tsin(5t)+cos(5t))}{25t}+\frac{c_{1})/t