What is the integral from 6 to 12 of 6e^x ?

The integral from 6 to 12 of 6e^x is 6(e^{12}-e^6)

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integral from 6 to 12 of 6e^x

\int_{6}^{12} 6 e^{x} d x

6 (e^{12} - e^{6})

Decimal Notation

974108.17575 \dots

Solution steps

\int_{6}^{12} 6 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{6}^{12} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 6 [e^{x}]_{6}^{12}

Compute the boundaries:

e^{12} - e^{6}

= 6 (e^{12} - e^{6})

y^{^{'}} = \frac{e ^{t - y}}{1 + e ^{t}}

x \to \infty lim (e^{- π})

\frac{d}{d x} (\frac{3 - x ^{2}}{2 x + 2})

\int x^{2} e^{- \frac{x}{4}} d x

What is the integral from 6 to 12 of 6e^x ?
The integral from 6 to 12 of 6e^x is 6(e^{12}-e^6)