What is the domain of f(x)=arctan((2x)/(1-x^2)) ?

The domain of f(x)=arctan((2x)/(1-x^2)) is x 1

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domain of f(x)=arctan((2x)/(1-x^2))

domain

f (x) = arctan (\frac{2 x}{1 - x ^{2}})

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{\partial}{\partial s} (1 + s t)

\int \frac{11 x + 64}{x ^{2} + 13 x + 40} d x

x \to 0 lim (\frac{( x ^{2} )}{e - 1})

\frac{\partial}{\partial x} (1 - x^{2} - x - 2 y^{2} + y)

What is the domain of f(x)=arctan((2x)/(1-x^2)) ?
The domain of f(x)=arctan((2x)/(1-x^2)) is x<-1\lor-1<x<1\lor x>1