What is the integral of (\sqrt[4]{x^5}) ?

The integral of (\sqrt[4]{x^5}) is 4/9 x^{9/4}+C

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integral of (\sqrt[4]{x^5})

\frac{4}{9} x^{\frac{9}{4}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{5}{4}} d x

Apply the Power Rule

: \frac{4}{9} x^{\frac{9}{4}}

= \frac{4}{9} x^{\frac{9}{4}}

Add a constant to the solution

= \frac{4}{9} x^{\frac{9}{4}} + C

\frac{\partial}{\partial s} (1 + s t)

\int \frac{11 x + 64}{x ^{2} + 13 x + 40} d x

x \to 0 lim (\frac{( x ^{2} )}{e - 1})

\frac{\partial}{\partial x} (1 - x^{2} - x - 2 y^{2} + y)

ln (2) + ln (x)

What is the integral of (\sqrt[4]{x^5}) ?
The integral of (\sqrt[4]{x^5}) is 4/9 x^{9/4}+C