What is inverse oflaplace 3s ?

The answer to inverse oflaplace 3s is 3\delta'(t)

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inverse oflaplace 3s

inverse laplace

3 s

3 δ' (t)

Solution steps

L^{- 1} {3 s}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {s}

L^{- 1} {s} : δ^{'} (t)

= 3 δ^{^{'}} (t)

y = 7 x + 5

9 (x^{3} - x)^{4}

\frac{\partial}{\partial x} (5 sin (2 (5 x + 6 y)))

\int x^{2} \cdot x^{3} + 1 d x

x \to 2 lim (\frac{x ^{3} - 1}{x - 1})

What is inverse oflaplace 3s ?
The answer to inverse oflaplace 3s is 3\delta'(t)