What is the derivative of (x-4)/(x+4) ?

The derivative of (x-4)/(x+4) is 8/((x+4)^2)

What is the first derivative of (x-4)/(x+4) ?

The first derivative of (x-4)/(x+4) is 8/((x+4)^2)

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derivative of

\frac{x - 4}{x + 4}

\frac{8}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 4}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 4 ) ( x + 4 ) - \frac{d}{d x} ( x + 4 ) ( x - 4 )}{( x + 4 ) ^{2}}

\frac{d}{d x} (x - 4) = 1

\frac{d}{d x} (x + 4) = 1

= \frac{1 \cdot ( x + 4 ) - 1 \cdot ( x - 4 )}{( x + 4 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 4 ) - 1 \cdot ( x - 4 )}{( x + 4 ) ^{2}} : \frac{8}{( x + 4 ) ^{2}}

= \frac{8}{( x + 4 ) ^{2}}

\frac{d y}{d x} = 2 y

x \to 0 lim (sin (\frac{40 π}{x}))

\frac{1}{( s + 2 ) ^{4}}

(\frac{4 x ^{2}}{2 - x})^{3}

\int - 2 ln (x^{2} - 1) d x

What is the derivative of (x-4)/(x+4) ?
The derivative of (x-4)/(x+4) is 8/((x+4)^2)
What is the first derivative of (x-4)/(x+4) ?
The first derivative of (x-4)/(x+4) is 8/((x+4)^2)