What is the integral of (-2)/((x+1)^2) ?

The integral of (-2)/((x+1)^2) is 2/(x+1)+C

Popular >

integral of (-2)/((x+1)^2)

\int \frac{- 2}{( x + 1 ) ^{2}} d x

\frac{2}{x + 1} + C

Solution steps

\int \frac{- 2}{( x + 1 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{( x + 1 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= - 2 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - 2 (- \frac{1}{u})

Substitute back

u = x + 1

= - 2 (- \frac{1}{x + 1})

Simplify

- 2 (- \frac{1}{x + 1}) : \frac{2}{x + 1}

= \frac{2}{x + 1}

Add a constant to the solution

= \frac{2}{x + 1} + C

\int \frac{9}{x 81 - ( ln ( x ) ) ^{2}} d x

\frac{d}{d x} (x + x)

3 x - 6 y x^{2} + 1 (\frac{d y}{d x}) = 0, y (0) = 3

x^{\frac{12}{7}}

(\frac{x}{7} + 1)^{\frac{3}{2}}

What is the integral of (-2)/((x+1)^2) ?
The integral of (-2)/((x+1)^2) is 2/(x+1)+C