What is the derivative of sqrt(x)+x ?

The derivative of sqrt(x)+x is 1/(2sqrt(x))+1

What is the first derivative of sqrt(x)+x ?

The first derivative of sqrt(x)+x is 1/(2sqrt(x))+1

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\frac{d}{d x} (x + x)

\frac{1}{2 x} + 1

Solution steps

\frac{d}{d x} (x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d x}{d x}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d x}{d x} = 1

= \frac{1}{2 x} + 1

3 x - 6 y x^{2} + 1 (\frac{d y}{d x}) = 0, y (0) = 3

x^{\frac{12}{7}}

(\frac{x}{7} + 1)^{\frac{3}{2}}

\int_{1}^{3} x^{2} + \frac{1}{4 x ^{2}} d x

3 x + π^{2}

What is the derivative of sqrt(x)+x ?
The derivative of sqrt(x)+x is 1/(2sqrt(x))+1
What is the first derivative of sqrt(x)+x ?
The first derivative of sqrt(x)+x is 1/(2sqrt(x))+1