What is the solution for (dy)/(dx)=(y-1)^2+0.01,y(0)=1 ?

The solution for (dy)/(dx)=(y-1)^2+0.01,y(0)=1 is y=(tan(x/(10)))/(10)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y-1)^2+0.01,y(0)=1

\frac{d y}{d x} = (y - 1)^{2} + 0.01, y (0) = 1

y = \frac{tan ( \frac{x}{10} )}{10} + 1

Solution steps

\frac{d y}{d x} = (y - 1)^{2} + 0.01

Solve separable ODE:

y = \frac{tan ( \frac{x}{10} )}{10} + 1

y = \frac{tan ( \frac{x}{10} )}{10} + 1

\frac{d}{d x} ((e^{x} - 1)^{2})

\int \frac{( x + 3 )}{x ^{2} + 11 x + 18} d x

\frac{d}{d y} (y e^{2 x y} + x)

y = ln (4 x)

\int \frac{- 2}{x ^{2}} d x

What is the solution for (dy)/(dx)=(y-1)^2+0.01,y(0)=1 ?
The solution for (dy)/(dx)=(y-1)^2+0.01,y(0)=1 is y=(tan(x/(10)))/(10)+1