What is the integral from-2 to 1 of x^3 ?

The integral from-2 to 1 of x^3 is -15/4

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integral from-2 to 1 of x^3

\int_{- 2}^{1} x^{3} d x

- \frac{15}{4}

Decimal Notation

- 3.75

Solution steps

\int_{- 2}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 2}^{1}

= [\frac{x ^{4}}{4}]_{- 2}^{1}

Compute the boundaries:

- \frac{15}{4}

= - \frac{15}{4}

\frac{2}{t ^{2}}

sin (x), cos (x), 0, \frac{π}{2}

(x - 1) y^{^{'}} - 2 + 3 x + y = 0

\int_{0}^{1} \frac{1}{e ^{x} + e ^{- x}} d x

\frac{d}{d x} (- 3 ln (3 + 4 x^{2}) + 5 x^{3} - 9)

What is the integral from-2 to 1 of x^3 ?
The integral from-2 to 1 of x^3 is -15/4