What is the solution for y^'=((y-y^2))/t ?

The solution for y^'=((y-y^2))/t is y=-(e^{c_{1}}t)/(1-e^{c_{1)}t}

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y^'=((y-y^2))/t

y^{^{'}} = \frac{( y - y ^{2} )}{t}

y = - \frac{e ^{c_{1}} t}{1 - e ^{c_{1}} t}

Solution steps

y^{'} (t) = \frac{( y - y ^{2} )}{t}

Solve separable ODE:

y = - \frac{e ^{c_{1}} t}{1 - e ^{c_{1}} t}

y = - \frac{e ^{c_{1}} t}{1 - e ^{c_{1}} t}

\frac{1}{s - 5}

y^{^{'}} + 6 y = 60, y (1) = 110

y^{^{'}} = 19 x y

\frac{s ^{2}}{s ^{3} + 2 \cdot s ^{2} - 1}

What is the solution for y^'=((y-y^2))/t ?
The solution for y^'=((y-y^2))/t is y=-(e^{c_{1}}t)/(1-e^{c_{1)}t}