What is the derivative of f(x)=(x^2+2)^2 ?

The derivative of f(x)=(x^2+2)^2 is 4x(x^2+2)

What is the first derivative of f(x)=(x^2+2)^2 ?

The first derivative of f(x)=(x^2+2)^2 is 4x(x^2+2)

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derivative of

f (x) = (x^{2} + 2)^{2}

4 x (x^{2} + 2)

Solution steps

\frac{d}{d x} ((x^{2} + 2)^{2})

Apply the chain rule:

2 (x^{2} + 2) \frac{d}{d x} (x^{2} + 2)

= 2 (x^{2} + 2) \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 2 (x^{2} + 2) \cdot 2 x

Simplify

= 4 x (x^{2} + 2)

f (x) = (8 x^{3} + 3 x^{2})^{3}

\frac{\partial}{\partial x} (2 x y - 2 x^{2} y)

x \to \infty lim (ln (5 x))

\int x x - 27 d x

\frac{d}{d x} (\frac{3}{x + 8})

What is the derivative of f(x)=(x^2+2)^2 ?
The derivative of f(x)=(x^2+2)^2 is 4x(x^2+2)
What is the first derivative of f(x)=(x^2+2)^2 ?
The first derivative of f(x)=(x^2+2)^2 is 4x(x^2+2)