What is the integral from 2 to infinity of 1/x ?

The integral from 2 to infinity of 1/x is diverges

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integral from 2 to infinity of 1/x

\int_{2}^{\infty} \frac{1}{x} d x

diverges

Solution steps

\int_{2}^{\infty} \frac{1}{x} d x

Compute the indefinite integral:

\int \frac{1}{x} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{x} d x =

diverges

= diverges

\int - 2.5 - \frac{1}{8} q d q

\frac{d}{d x} (e^{s e c (x^{2})})

x \to 0 + lim (\frac{ln ( x + 1 )}{x})

sin (3 x) + cos (8 x)

(1 + x^{2}) (\frac{d y}{d x}) - 2 x y = 0

What is the integral from 2 to infinity of 1/x ?
The integral from 2 to infinity of 1/x is diverges