What is the derivative of 3x^4-65x^3 ?

The derivative of 3x^4-65x^3 is 12x^3-195x^2

What is the first derivative of 3x^4-65x^3 ?

The first derivative of 3x^4-65x^3 is 12x^3-195x^2

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derivative of

3 x^{4} - 65 x^{3}

12 x^{3} - 195 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 65 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (65 x^{3})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (65 x^{3}) = 195 x^{2}

= 12 x^{3} - 195 x^{2}

\int 2 sec^{4} (x) d x

\int - \frac{5000}{x ^{2}} d x

\frac{d}{d x} (2^{x} + 3^{x})

- 5 t (3 t^{8} - 1)^{7}

\frac{d}{d x} (\frac{3 x ^{2} + 5 x}{x})

What is the derivative of 3x^4-65x^3 ?
The derivative of 3x^4-65x^3 is 12x^3-195x^2
What is the first derivative of 3x^4-65x^3 ?
The first derivative of 3x^4-65x^3 is 12x^3-195x^2