What is the integral of-(5000)/(x^2) ?

The integral of-(5000)/(x^2) is (5000)/x+C

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integral of-(5000)/(x^2)

\int - \frac{5000}{x ^{2}} d x

\frac{5000}{x} + C

Solution steps

\int - \frac{5000}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5000 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 5000 (- \frac{1}{x})

Simplify

- 5000 (- \frac{1}{x}) : \frac{5000}{x}

= \frac{5000}{x}

Add a constant to the solution

= \frac{5000}{x} + C

\frac{d}{d x} (2^{x} + 3^{x})

- 5 t (3 t^{8} - 1)^{7}

\frac{d}{d x} (\frac{3 x ^{2} + 5 x}{x})

\frac{d s}{\frac{d t}{2}} = s

\frac{d ^{10}}{d x ^{10}} (cos (2 x))

What is the integral of-(5000)/(x^2) ?
The integral of-(5000)/(x^2) is (5000)/x+C