What is the derivative of 2^x+3^x ?

The derivative of 2^x+3^x is 2^xln(2)+3^xln(3)

What is the first derivative of 2^x+3^x ?

The first derivative of 2^x+3^x is 2^xln(2)+3^xln(3)

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\frac{d}{d x} (2^{x} + 3^{x})

2^{x} ln (2) + 3^{x} ln (3)

Solution steps

\frac{d}{d x} (2^{x} + 3^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d}{d x} (3^{x})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= 2^{x} ln (2) + 3^{x} ln (3)

- 5 t (3 t^{8} - 1)^{7}

\frac{d}{d x} (\frac{3 x ^{2} + 5 x}{x})

\frac{d s}{\frac{d t}{2}} = s

\frac{d ^{10}}{d x ^{10}} (cos (2 x))

t^{2} \cdot \frac{d x}{d t} = \frac{1}{x}

What is the derivative of 2^x+3^x ?
The derivative of 2^x+3^x is 2^xln(2)+3^xln(3)
What is the first derivative of 2^x+3^x ?
The first derivative of 2^x+3^x is 2^xln(2)+3^xln(3)