What is the derivative of \sqrt[3]{x+7} ?

The derivative of \sqrt[3]{x+7} is 1/(3(x+7)^{2/3)}

What is the first derivative of \sqrt[3]{x+7} ?

The first derivative of \sqrt[3]{x+7} is 1/(3(x+7)^{2/3)}

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\frac{1}{3 ( x + 7 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x + 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (x + 7)

= \frac{1}{3 ( x + 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (x + 7)

\frac{d}{d x} (x + 7) = 1

= \frac{1}{3 ( x + 7 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x + 7 ) ^{\frac{2}{3}}}

x y^{^{''}} + 5 y^{^{'}} = 0

\frac{\partial}{\partial y} (5 x y^{3})

y = x^{2} + 5 x + 2, (- 5, 2)

f (x) = - 3 - 6 x^{2}, (- 2, 27)

f (t) = t sin (t)

What is the derivative of \sqrt[3]{x+7} ?
The derivative of \sqrt[3]{x+7} is 1/(3(x+7)^{2/3)}
What is the first derivative of \sqrt[3]{x+7} ?
The first derivative of \sqrt[3]{x+7} is 1/(3(x+7)^{2/3)}