What is the derivative of-6/((1-x)^4) ?

The derivative of-6/((1-x)^4) is -(24)/((1-x)^5)

What is the first derivative of-6/((1-x)^4) ?

The first derivative of-6/((1-x)^4) is -(24)/((1-x)^5)

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derivative of

- \frac{6}{( 1 - x ) ^{4}}

- \frac{24}{( 1 - x ) ^{5}}

Solution steps

\frac{d}{d x} (- \frac{6}{( 1 - x ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 6 \frac{d}{d x} ((1 - x)^{- 4})

Apply the chain rule:

- \frac{4}{( 1 - x ) ^{5}} \frac{d}{d x} (1 - x)

= - \frac{4}{( 1 - x ) ^{5}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= - 6 (- \frac{4}{( 1 - x ) ^{5}} (- 1))

Simplify

- 6 (- \frac{4}{( 1 - x ) ^{5}} (- 1)) : - \frac{24}{( 1 - x ) ^{5}}

= - \frac{24}{( 1 - x ) ^{5}}

\frac{d ^{2}}{d x ^{2}} ((- 6 - 7 t)^{6})

\int_{1}^{4} t d t

y^{^{'}} = e^{y + 2 x}

\int_{0}^{1} (\frac{3 t ^{2}}{1 + t ^{3}}) d t

\int \frac{1}{6 + x} d x

What is the derivative of-6/((1-x)^4) ?
The derivative of-6/((1-x)^4) is -(24)/((1-x)^5)
What is the first derivative of-6/((1-x)^4) ?
The first derivative of-6/((1-x)^4) is -(24)/((1-x)^5)