What is the derivative of y=1-(x^2)/(36) ?

The derivative of y=1-(x^2)/(36) is -x/(18)

What is the first derivative of y=1-(x^2)/(36) ?

The first derivative of y=1-(x^2)/(36) is -x/(18)

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derivative of

y = 1 - \frac{x ^{2}}{36}

- \frac{x}{18}

Solution steps

\frac{d}{d x} (1 - \frac{x ^{2}}{36})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{x ^{2}}{36})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{x ^{2}}{36}) = \frac{x}{18}

= 0 - \frac{x}{18}

Simplify

= - \frac{x}{18}

\frac{\partial}{\partial z} (2 y + z)

\int \frac{arcsin ( 5 x )}{1 - 25 x ^{2}} d x

t^{2} y^{^{''}} + 11 t y^{^{'}} + 25 y = 0

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 2 y^{2}})

\int \frac{t ^{3} + 2}{t ^{4} + 8 t - 3} d t

What is the derivative of y=1-(x^2)/(36) ?
The derivative of y=1-(x^2)/(36) is -x/(18)
What is the first derivative of y=1-(x^2)/(36) ?
The first derivative of y=1-(x^2)/(36) is -x/(18)