What is the derivative of 2(x^3-x)^4 ?

The derivative of 2(x^3-x)^4 is 8(x^3-x)^3(3x^2-1)

What is the first derivative of 2(x^3-x)^4 ?

The first derivative of 2(x^3-x)^4 is 8(x^3-x)^3(3x^2-1)

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derivative of

2 (x^{3} - x)^{4}

8 (x^{3} - x)^{3} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (2 (x^{3} - x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x^{3} - x)^{4})

Apply the chain rule:

4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

= 4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= 2 \cdot 4 (x^{3} - x)^{3} (3 x^{2} - 1)

Simplify

= 8 (x^{3} - x)^{3} (3 x^{2} - 1)

n = 2 \sum \infty \frac{2}{n ^{3}}

n = 0 \sum \infty 2^{2 n}

\frac{d}{d x} (a^{f (x)})

\int e^{- θ} cos (2 θ) d θ

\int \frac{19 arctan ( x )}{x ^{2}} d x

What is the derivative of 2(x^3-x)^4 ?
The derivative of 2(x^3-x)^4 is 8(x^3-x)^3(3x^2-1)
What is the first derivative of 2(x^3-x)^4 ?
The first derivative of 2(x^3-x)^4 is 8(x^3-x)^3(3x^2-1)