What is the solution for f^{''}(x)=x^{-3/2} ?

The solution for f^{''}(x)=x^{-3/2} is f(x)=-4x^{1/2}+c_{1}x+c_{2}

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f^{''}(x)=x^{-3/2}

f^{^{''}} (x) = x^{- \frac{3}{2}}

f (x) = - 4 x^{\frac{1}{2}} + c_{1} x + c_{2}

Solution steps

f^{''} (x) = x^{- \frac{3}{2}}

Solve

f^{''} (x) = x^{- \frac{3}{2}} : f^{'} (x) = - \frac{2}{x ^{\frac{1}{2}}} + c_{1}

Solve

f^{'} (x) = - \frac{2}{x ^{\frac{1}{2}}} + c_{1} : f (x) = - 4 x^{\frac{1}{2}} + c_{1} x + c_{2}

f (x) = - 4 x^{\frac{1}{2}} + c_{1} x + c_{2}

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What is the solution for f^{''}(x)=x^{-3/2} ?
The solution for f^{''}(x)=x^{-3/2} is f(x)=-4x^{1/2}+c_{1}x+c_{2}