What is area f(x)=e^x,g(x)=2-e^x,[0,3] ?

The answer to area f(x)=e^x,g(x)=2-e^x,[0,3] is 2e^3-8

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area f(x)=e^x,g(x)=2-e^x,[0,3]

area

f (x) = e^{x}, g (x) = 2 - e^{x}, [0, 3]

2 e^{3} - 8

Decimal Notation

32.17107 \dots

Solution steps

Apply the area formula:

\int_{0}^{3} ∣ e^{x} - (2 - e^{x}) ∣ d x

Solve

\int_{0}^{3} ∣ e^{x} - (2 - e^{x}) ∣ d x : 2 e^{3} - 8

The area is:

= 2 e^{3} - 8

\frac{d}{d x} (x^{\frac{2}{3}} (x^{2} - 4))

n = 1 \sum \infty \frac{8 ^{n}}{9 ^{n}}

\int_{- \infty}^{- 1} \frac{1}{x ^{3}} d x

\frac{d}{d x} (1 - 2 sin (x))

f (x) = 6 e^{x}

What is area f(x)=e^x,g(x)=2-e^x,[0,3] ?
The answer to area f(x)=e^x,g(x)=2-e^x,[0,3] is 2e^3-8