What is the derivative of y=(9x^2+4x+4)^5 ?

The derivative of y=(9x^2+4x+4)^5 is 5(9x^2+4x+4)^4(18x+4)

What is the first derivative of y=(9x^2+4x+4)^5 ?

The first derivative of y=(9x^2+4x+4)^5 is 5(9x^2+4x+4)^4(18x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = (9 x^{2} + 4 x + 4)^{5}

5 (9 x^{2} + 4 x + 4)^{4} (18 x + 4)

Solution steps

\frac{d}{d x} ((9 x^{2} + 4 x + 4)^{5})

Apply the chain rule:

5 (9 x^{2} + 4 x + 4)^{4} \frac{d}{d x} (9 x^{2} + 4 x + 4)

= 5 (9 x^{2} + 4 x + 4)^{4} \frac{d}{d x} (9 x^{2} + 4 x + 4)

\frac{d}{d x} (9 x^{2} + 4 x + 4) = 18 x + 4

= 5 (9 x^{2} + 4 x + 4)^{4} (18 x + 4)

3 - 2 e^{- 4 t}

\int \frac{2 x ^{2} + 5}{x ^{2} + 1} d x

\frac{d}{d y} (\frac{z}{x ^{2} + y ^{2} + z ^{2}})

e^{3 t^{2}}

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

What is the derivative of y=(9x^2+4x+4)^5 ?
The derivative of y=(9x^2+4x+4)^5 is 5(9x^2+4x+4)^4(18x+4)
What is the first derivative of y=(9x^2+4x+4)^5 ?
The first derivative of y=(9x^2+4x+4)^5 is 5(9x^2+4x+4)^4(18x+4)