What is the derivative of (2x^3+1^2) ?

The derivative of (2x^3+1^2) is 12x^2(2x^3+1)

What is the first derivative of (2x^3+1^2) ?

The first derivative of (2x^3+1^2) is 12x^2(2x^3+1)

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\frac{d}{d x} ((2 x^{3} + 1)^{2})

12 x^{2} (2 x^{3} + 1)

Solution steps

\frac{d}{d x} ((2 x^{3} + 1)^{2})

Apply the chain rule:

2 (2 x^{3} + 1) \frac{d}{d x} (2 x^{3} + 1)

= 2 (2 x^{3} + 1) \frac{d}{d x} (2 x^{3} + 1)

\frac{d}{d x} (2 x^{3} + 1) = 6 x^{2}

= 2 (2 x^{3} + 1) \cdot 6 x^{2}

Simplify

= 12 x^{2} (2 x^{3} + 1)

(2, 6), (6, 6)

\frac{d}{d x} (- 6 sin (x) - 3 x)

\int x^{4} (x^{5} - 7)^{6} d x

\frac{8}{s - 3}

\frac{d}{d x} (2 sin (x) + 4 cos (x))

What is the derivative of (2x^3+1^2) ?
The derivative of (2x^3+1^2) is 12x^2(2x^3+1)
What is the first derivative of (2x^3+1^2) ?
The first derivative of (2x^3+1^2) is 12x^2(2x^3+1)