What is the derivative of (x^6/3) ?

The derivative of (x^6/3) is 2x^5

What is the first derivative of (x^6/3) ?

The first derivative of (x^6/3) is 2x^5

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\frac{d}{d x} (\frac{x ^{6}}{3})

2 x^{5}

Solution steps

\frac{d}{d x} (\frac{x ^{6}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (x^{6})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} \cdot 6 x^{6 - 1}

Simplify

\frac{1}{3} \cdot 6 x^{6 - 1} : 2 x^{5}

= 2 x^{5}

\int 6 x^{2} cos (2 x^{3} + 1) d x

x + 3

\frac{d y}{d x} = y (1 - 0.0004 y)

(e^{x} - 2 x y) d x - x^{2} d y = 0

2 e^{- 3 x}

What is the derivative of (x^6/3) ?
The derivative of (x^6/3) is 2x^5
What is the first derivative of (x^6/3) ?
The first derivative of (x^6/3) is 2x^5