What is the derivative of (4x/(x+2)) ?

The derivative of (4x/(x+2)) is 8/((x+2)^2)

What is the first derivative of (4x/(x+2)) ?

The first derivative of (4x/(x+2)) is 8/((x+2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{4 x}{x + 2})

\frac{8}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{x + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( x + 2 ) - \frac{d}{d x} ( x + 2 ) x}{( x + 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 2) = 1

= 4 \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot x}{( x + 2 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot x}{( x + 2 ) ^{2}} : \frac{8}{( x + 2 ) ^{2}}

= \frac{8}{( x + 2 ) ^{2}}

f (x) = 64 - x^{2}

\frac{\partial}{\partial x} (x y cos (5 yz))

\int (x e^{x^{2}}) d x

\frac{d}{d x} (ln (x^{2} + 12))

csc (x), at x = \frac{π}{6}

What is the derivative of (4x/(x+2)) ?
The derivative of (4x/(x+2)) is 8/((x+2)^2)
What is the first derivative of (4x/(x+2)) ?
The first derivative of (4x/(x+2)) is 8/((x+2)^2)