What is the solution for 4xy^'-16y=x^{-7},y(1)=7 ?

The solution for 4xy^'-16y=x^{-7},y(1)=7 is y=-1/(44x^7)+(309x^4)/(44)

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4xy^'-16y=x^{-7},y(1)=7

4 x y^{^{'}} - 16 y = x^{- 7}, y (1) = 7

y = - \frac{1}{44 x ^{7}} + \frac{309 x ^{4}}{44}

Solution steps

4 x y^{'} (x) - 16 y = x^{- 7}

Solve linear ODE:

y = - \frac{1}{44 x ^{7}} + \frac{309 x ^{4}}{44}

y = - \frac{1}{44 x ^{7}} + \frac{309 x ^{4}}{44}

\frac{\partial}{\partial y} (3 x^{2} - 2 x y - y)

y = \frac{8}{sin ( x )} + \frac{1}{cot ( x )}

x \to 0 lim (\frac{5}{1 + e ^{\frac{1}{x}}})

\frac{\partial}{\partial x} (48 x^{5} y^{7} - 35 x^{4} y^{6})

f (x) = \frac{6}{( 1 + e ^{- x} ) , at ( 0 , 3 )}

What is the solution for 4xy^'-16y=x^{-7},y(1)=7 ?
The solution for 4xy^'-16y=x^{-7},y(1)=7 is y=-1/(44x^7)+(309x^4)/(44)