What is the solution for (1-x)y^'-4xy^'+5y=cos(x) ?

The solution for (1-x)y^'-4xy^'+5y=cos(x) is y=(1-5x)*integral of (cos(x))/((1-5x)^2)

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(1-x)y^'-4xy^'+5y=cos(x)

(1 - x) y^{^{'}} - 4 x y^{^{'}} + 5 y = cos (x)

y = (1 - 5 x) \cdot \int \frac{cos ( x )}{( 1 - 5 x ) ^{2}} d x

Solution steps

(1 - x) y^{'} (x) - 4 x y^{'} (x) + 5 y = cos (x)

Solve linear ODE:

y = (1 - 5 x) \cdot \int \frac{cos ( x )}{( 1 - 5 x ) ^{2}} d x

y = (1 - 5 x) \cdot \int \frac{cos ( x )}{( 1 - 5 x ) ^{2}} d x

\frac{d}{d x} (\frac{1 - x}{e ^{x}})

\frac{\partial}{\partial x} (- y cos (- 3 x))

n = 2 \sum \infty \frac{( n - 1 )}{n}

- x^{4} + 2 x^{3} + 4 x^{2}

f (x) = 3 x^{2} + 2

What is the solution for (1-x)y^'-4xy^'+5y=cos(x) ?
The solution for (1-x)y^'-4xy^'+5y=cos(x) is y=(1-5x)*integral of (cos(x))/((1-5x)^2)