What is derivative of f(x)=dcos(t)+t^2sin(t) ?

The answer to derivative of f(x)=dcos(t)+t^2sin(t) is (dt)/(dx)=0

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derivative of f(x)=dcos(t)+t^2sin(t)

derivative of

f (x) = d cos (t) + t^{2} sin (t)

\frac{d t}{d x} = 0

Solution steps

f (x) = d cos (t) + t^{2} sin (t)

Treat

t

t (x)

Differentiate both sides:

0 = - d sin (t) \frac{d t}{d x} + 2 t \frac{d t}{d x} sin (t) + cos (t) \frac{d t}{d x} t^{2}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d}{d t} (1 + 4 t)

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (\frac{π}{2}) = 0, y^{^{'}} (\frac{π}{2}) = 2

x \to 0 lim ((ln (x)) - \frac{1}{x})

x \to - 2 lim (- (x^{2} - x + 1))

\int_{1}^{2} x^{10} d x

What is derivative of f(x)=dcos(t)+t^2sin(t) ?
The answer to derivative of f(x)=dcos(t)+t^2sin(t) is (dt)/(dx)=0