What is (\partial)/(\partial x)(x^2-7x+12) ?

The answer to (\partial)/(\partial x)(x^2-7x+12) is 2x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2-7x+12)

\frac{\partial}{\partial x} (x^{2} - 7 x + 12)

2 x - 7

Solution steps

\frac{\partial}{\partial x} (x^{2} - 7 x + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (7 x) + \frac{\partial}{\partial x} (12)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (12) = 0

= 2 x - 7 + 0

Simplify

= 2 x - 7

\int \frac{x}{x ^{4} - 16} d x

x^{2} y^{^{''}} - 7 x y^{^{'}} + 12 y = 0

\int \frac{x}{cos ^{2} ( x ^{2} )} d x

\int x^{2} sin (x z) d z

x \to 0 lim (\frac{x + 2 - 2}{2 x + 5 - 3})

What is (\partial)/(\partial x)(x^2-7x+12) ?
The answer to (\partial)/(\partial x)(x^2-7x+12) is 2x-7