What is the derivative of y=x^2+1 ?

The derivative of y=x^2+1 is 2x

What is the first derivative of y=x^2+1 ?

The first derivative of y=x^2+1 is 2x

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derivative of

y = x^{2} + 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d}{d x} (2 1 + x)

f (x) = (x + 1)^{2}

y^{^{''}} + 324 y = sec (18 x)

x \to 18 lim (\frac{x ^{2}}{2} - \frac{9}{x})

y^{^{'}} = 2 (3 x + y)^{2} - 1