What is the d/(dt)(tan(sec(cos(t)))) ?

The d/(dt)(tan(sec(cos(t)))) is -sec^2(sec(cos(t)))sec(cos(t))tan(cos(t))sin(t)

What is the first d/(dt)(tan(sec(cos(t)))) ?

The first d/(dt)(tan(sec(cos(t)))) is -sec^2(sec(cos(t)))sec(cos(t))tan(cos(t))sin(t)

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\frac{d}{d t} (tan (sec (cos (t))))

- sec^{2} (sec (cos (t))) sec (cos (t)) tan (cos (t)) sin (t)

Solution steps

\frac{d}{d t} (tan (sec (cos (t))))

Apply the chain rule:

sec^{2} (sec (cos (t))) \frac{d}{d t} (sec (cos (t)))

= sec^{2} (sec (cos (t))) \frac{d}{d t} (sec (cos (t)))

\frac{d}{d t} (sec (cos (t))) = - sec (cos (t)) tan (cos (t)) sin (t)

= sec^{2} (sec (cos (t))) (- sec (cos (t)) tan (cos (t)) sin (t))

Simplify

= - sec^{2} (sec (cos (t))) sec (cos (t)) tan (cos (t)) sin (t)

\int (1 + x y) d y

n = 0 \sum \infty \frac{1}{3 n + 1}

(\frac{2}{x})^{^{'}}

\int_{- 1}^{1} \frac{1}{2} x^{2} d x

\frac{d y}{d x} = y (y^{2} - 1)

What is the d/(dt)(tan(sec(cos(t)))) ?
The d/(dt)(tan(sec(cos(t)))) is -sec^2(sec(cos(t)))sec(cos(t))tan(cos(t))sin(t)
What is the first d/(dt)(tan(sec(cos(t)))) ?
The first d/(dt)(tan(sec(cos(t)))) is -sec^2(sec(cos(t)))sec(cos(t))tan(cos(t))sin(t)