What is the solution for (dy)/(dx)=y(y^2-1) ?

The solution for (dy)/(dx)=y(y^2-1) is y=sqrt(1/(-e^{2x+c_{1))+1}},y=-sqrt(1/(-e^{2x+c_{1))+1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=y(y^2-1)

\frac{d y}{d x} = y (y^{2} - 1)

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

Solution steps

\frac{d y}{d x} = y (y^{2} - 1)

Solve Bernoulli ODE:

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

y = x^{2} + 2 x - 4

y = x^{3} + 3 x^{2}

\frac{\partial}{\partial x} (2 cos (y))

\frac{1}{5 x ^{2}}

\frac{\partial}{\partial x} (tan (3 x))

What is the solution for (dy)/(dx)=y(y^2-1) ?
The solution for (dy)/(dx)=y(y^2-1) is y=sqrt(1/(-e^{2x+c_{1))+1}},y=-sqrt(1/(-e^{2x+c_{1))+1}}