(2/x)^'

Solution

(\frac{2}{x})^{^{'}}

- \frac{2}{x ^{2}}

Solution steps

(\frac{2}{x})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (\frac{1}{x})^{^{'}}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 (x^{- 1})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 1 \cdot x^{- 1 - 1})

Simplify

2 (- 1 \cdot x^{- 1 - 1}) : - \frac{2}{x ^{2}}

= - \frac{2}{x ^{2}}

\int_{- 1}^{1} \frac{1}{2} x^{2} d x

\frac{d y}{d x} = y (y^{2} - 1)

y = x^{2} + 2 x - 4

y = x^{3} + 3 x^{2}

\frac{\partial}{\partial x} (2 cos (y))