What is the integral of 1/(x^2+1) ?

The integral of 1/(x^2+1) is arctan(x)+C

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integral of 1/(x^2+1)

\int \frac{1}{x ^{2} + 1} d x

arctan (x) + C

Solution steps

\int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

\frac{\partial}{\partial x} (z sin (x))

\frac{d}{d x} (ln (4 x^{2}))

sin^{2} (x), sin^{4} (x), 0, π

\frac{d}{d x} ((2)^{x})

4 x - x^{2}