What is the tangent of f(x)=x^3-2x-2,\at x=-1 ?

The tangent of f(x)=x^3-2x-2,\at x=-1 is y=x

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tangent of f(x)=x^3-2x-2,\at x=-1

tangent of

f (x) = x^{3} - 2 x - 2, at x = - 1

y = x

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

f (x) = x^{3} - 2 x - 2 : \frac{df ( x )}{d x} = 3 x^{2} - 2

Compute the slope of

f (x) = x^{3} - 2 x - 2

x = - 1 : m = 1

Find the line with slope m=

1

and passing through

(- 1, - 1) : y = x

y = x

f (t) = \frac{9}{t ^{2}}

x (y^{^{'}}) = 4 y

x^{3} + 2

\int 4 ln (x^{2} - 1) d x

\int 2 x^{2} - 4 x - 6 d x

What is the tangent of f(x)=x^3-2x-2,\at x=-1 ?
The tangent of f(x)=x^3-2x-2,\at x=-1 is y=x