What is the derivative of (2x^2+3x^2) ?

The derivative of (2x^2+3x^2) is 2(2x^2+3x)(4x+3)

What is the first derivative of (2x^2+3x^2) ?

The first derivative of (2x^2+3x^2) is 2(2x^2+3x)(4x+3)

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\frac{d}{d x} ((2 x^{2} + 3 x)^{2})

2 (2 x^{2} + 3 x) (4 x + 3)

Solution steps

\frac{d}{d x} ((2 x^{2} + 3 x)^{2})

Apply the chain rule:

2 (2 x^{2} + 3 x) \frac{d}{d x} (2 x^{2} + 3 x)

= 2 (2 x^{2} + 3 x) \frac{d}{d x} (2 x^{2} + 3 x)

\frac{d}{d x} (2 x^{2} + 3 x) = 4 x + 3

= 2 (2 x^{2} + 3 x) (4 x + 3)

y^{^{''}} + 2 y = - 12 x

h \to 0 lim (\frac{( 2 + h ) ^{3} - 8}{h})

x \to \infty lim (x)

f (x) =, 4 x^{3} + 2 t + 9

What is the derivative of (2x^2+3x^2) ?
The derivative of (2x^2+3x^2) is 2(2x^2+3x)(4x+3)
What is the first derivative of (2x^2+3x^2) ?
The first derivative of (2x^2+3x^2) is 2(2x^2+3x)(4x+3)